49a^2+42a+9=0

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Solution for 49a^2+42a+9=0 equation: 



49a^2+42a+9=0

a = 49; b = 42; c = +9;
Δ = b2-4ac
Δ = 422-4·49·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-42}{98}=-3/7$

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